Duty cycle of clock

Duty cycle: Duty cycle of a clock is defined as the fraction of a period of clock during which the clock is in active state. Duty cycle of a clock is normally expressed as a percentage. For instance, figure below shows a clock having an active state of '1' stays low for 2 ns during its period of 10 ns. It is, therefore, said to have a duty cycle of 20%.

How duty cycle impacts timing: Duty cycle of clock plays a big role in timing closure of designs. We need to consider following factors related to duty cycle variation while timing:

• Half cycle timing paths: If there are both positive and negative edge-triggered flip-flops in the design, duty cycle of the clock matters a lot. For instance, if we have a clock of 100 MHz with 20% duty cycle; For a timing path from positive edge-triggered flip-flop to negative edge-triggered flip-flop, we get only 2 ns for setup timing for positive-to-negative path and 8 ns for negative-to-positive path as compared to 10 ns for a full cycle path. However, if the same clock had duty cycle of 50%, we would have got 5 ns for the same half cycle timng path.

• Minimum pulse width requirements: At high frequencies, duty cycle matters a lot. For instance, every sequential element has requirement of minimum pulse width that should reach it (read this). If the duty cycle of the clock is not close to 50%, we are limited in providing high frequency even if we are capable of meeting timing at even higher frequencies. Let us take an example. If the minimum pulse width requirement of a flip-flop is 500 ps, then with 50% duty cycle clock, we can use a clock of 1 GHz (1 ns clock period). But if we use a clock of duty cycle of 20%, we cannot use a clock greater than 400 MHz.

With the above things in mind, it makes sense to use a clock with duty cycle as close to 50%. However, in many scenarios, it may not be feasible to do so. So, one needs to decide the priorities; i.e., architecture complexities vs timing complexities. Generating a divided clock of 50% duty cycle is not always possible and there are a few complexities involved in architecture. For instance, clock waveform synchronization between the clocks if there are multiple dividers. Also, for odd division factors like divide_by_3 etc., we need more complex divider circuitry than what may be required for divide_by_2 or divide_by_4 etc.

Also read:

• Interview questions related to clock jitter and duty cycle variations

Which type of jitter matters for timing slack calculation?

In the post Clock jitter, we learnt about the basics of clock jitter. We also learned about different types of clock jitter. Now, the question arises as to what type of clock jitter is useful for calculation of timing slack, both setup and hold slacks. We will gradually try to build understanding for the same.

If we look into the equation of setup slack for a positive edge-triggered flip-flop to another positive edge-triggered flip-flop, we see that setup slack depends upon "clock period". Now, if look closely, we will find that the clock period that we are talking about is actually distance between two clock edges. The larger the distance between the clock edges, greater will be the clock period. Hence, more positive will be setup slack.

 Now, period jitter represents the absolute deviation of clock period from its ideal clock period. So, the jitter we should be looking for is maximum value of "peak-to-peak period jitter". Peak-to-peak period jitter can either increase or decrease clock period. But, we need to take the effect of jitter to decrease clock period. This is because we have to take the worst case of clock period to have most pessimistic setup slack value. And the worst clock period will occur when peak-to-peak jitter is maximum.

So, we can say that for setup slack calculation,

Clock period (actual) = Clock period (ideal) - peak-to-peak jitter (maximum)

What will happen to clock jitter if I divide down the clock?

As we have discussed above, due to clock jitter, for setup calculation, we will assume that peak-to-peak period jitter has caused edge 2 to come closer to edge 1, thereby reducing actual clock period by that margin. Similarly, edge 3 can come closer to edge 2. So, ideally, if we look at DIV_2 clock, the possible jitter here should be 2 times the jitter of SOURCE_CLOCK. Similarly, a DIV_4 clock is expected to have 4 times the jitter and a DIV_8 clock is expected to have 8 times the jitter. And so on..

Now comes the tricky part. As per the definition of long term jitter, nth edge of clock cannot have a jitter more than long term jitter. So, if I say that a PLL has a long term jitter spec of 6 times that of maximum peak-to-peak period jitter, then a DIV_8 clock will have peak-to-peak jitter equal to 6 times the peak-to-peak period jitter of SOURCE_CLOCK. Even a DIV_16 clock will have same maximum jitter.


What will happen to clock jitter for a multicycle path?
Similar to the case of divided down version of clock, a multicycle path also involves other than consecutive edges. So, similar concepts will apply here. So, a multicycle path for setup of 2 will have a jitter of 2 times the peak-to-peak jitter of SOURCE_CLOCK, etc.

Also read:

• Interview questions related to clock jitter and duty cycle variations