How to fix min pulse width violation

In our previous posts, we discussed about the duty cycle, duty cycle variation and duty cycle degradation. Bad duty cycle impacts half cycle timing paths and has impact in meeting timing for minimum pulse width checks of flip-flops. However, there are certain techniques available that can help you in improving the duty cycle of the clock. We will discuss these techniques in this post as below:

1. Dual inversion in clock branch: A certain category of logic cells are more probable of having one of the rise or fall delays greater than the other. A chain of such cells will make either high pulse of clock shorter or low pulse of clock shorter. One can use an inverter in the middle of the chain as shown in figure below to tackle this. Doing this, what we are essentially doing is converting rise edges to fall and vice-versa. So, the shortening of pulse of first few elements is balanced with the rest of the elements. In the below figure, there are 20 buffers, each shortening the pulse by 10 ps. The output of 10th buffer will have a shorter pulse as compared to clock source. The inverter at the output of 10th buffer will feed an inverted clock to 11th buffer. This will have high pulse which is greater than low pulse. Rest of the chain will try to reduce this pulse. In the end, we get a pulse which is equal to what was available at the source.

One can also try an all-inverter clock tree. In an all-inverter clock tree, every element will change the sense of clock pulse; thereby minimizing the clock pulse distortion.

However, this kind of delay balancing will only work where there is inherent variation of delays in rise vs fall. It will not work in case of OCV variations. So, if the chain length is arbitrarily large, our second method will come to rescue.

2. Even division to tackle duty cycle degradation: Suppose there is source clock with very poor duty cycle (say 10%) and you divide down the clock by 2 with a flip-flop divider. What we observe is amazing. The resulting clock is having almost 50% duty cycle. So, whenever we need an output clock with perfect duty cycle, we can use a divider to divide down the clock. The only drawback of this method is that we need a source clock of frequency twice than what is required to be timed!!

There are a few things to be kept in mind for this method:

• This method will improve the duty cycle of clock at the output of the flop. Degradation in duty cycle happening after the divider, if any, will be there.

• Duty cycle of the input clock at flip-flop must be within the limits of what is required to be minimum pulse width at the flip-flop.

Also read:

• Interview questions related to clock jitter and duty cycle variations

Duty cycle degradation

In the post, we discussed about duty cycle variation of the clock source. However, this is not the only pain in half cycle timing paths. Along clock path also, duty cycle of the clock can degrade. This can effect timing of half cycle paths adversely. We will discuss this in some detail; and also discuss how to tackle this. 

How is there degradation in duty cycle of clock: In addition to source duty cycle variation, there can be assymmetry in rise delay vs fall delay of clock elements. For instance, a buffer may have nominal rise (0 -> 1) delay of 50 ns whereas 48 ns for fall delay (1 -> 0). So, if a clock pulse passes through it, it will eat a portion of this clock pulse as shown in figure 1 below. For more clarity, we have exaggerated the scenario with a fall delay of 30 ns.

There are a lot of delay elements in clock distribution networks (also called clock tree network) inside the SoC. So, this problem is bound to happen there. Let us say, clock path has 20 buffers, each having a rise delay 10 ps greater than fall delay. So, the high pulse will get shortened when the clock reaches its sink. See how the pulse gets shortened if there is asymmetry in rise vs fall delay of a delay element or logic gate in below figure.

Even if we assume that the delay element has rise delay equal to fall delay, still, there is possibility of duty cycle degradation. Normally, a buffer (or inverter) has a nominal delay with some delay variations (for instance, OCVs) to be taken into account. For instance, it may have a rise delay of 100 ps with OCV variation to be taken of 5%. So, depending upon the scenario, we need to take its delay as either 95 ps or 105 ps. Similarly, even if we say that fall delay is exactly equal to rise delay, even then because of OCV variations, fall delay to be taken into account will be different than rise delay. Let us suppose, there are 20 such buffers in clock path with an ideal clock source. Then, we will have uncertainty in arrival of both rise and fall edges. And the effect will be visible in timing paths' slack.

How duty cycle degradation impacts timing: Degradation in duty cycle impacts timing wherever both rising and falling edges of clock are involved. For instance, it will impact half cycle timing paths as well as minimum pulse width check. You can go through our post duty cycle of clock to have an idea of the impact.

Also read:

• Interview questions related to clock jitter and duty cycle variations